题解 | #迷宫问题#
迷宫问题
https://www.nowcoder.com/practice/cf24906056f4488c9ddb132f317e03bc
#include <iostream> #include <queue> #include <sys/ucontext.h> #include <vector> using namespace std; #define N 100 int dp[N][N]; int n; int m; int dfs(int x, int y, vector<vector<int>>& q) { if (x >= n || x < 0 || y < 0 || y >= m) return -1; if(x == n - 1 && y == m - 1) return 1; if(dp[x][y] != 0) return -1; q.push_back({x, y}); dp[x][y] = -1; int dirs[4][2] = { {-1, 0}, {0, 1}, {1, 0}, {0, -1} }; for(int i = 0; i < 4; i++){ if(dfs(x + dirs[i][0], y + dirs[i][1], q) == 1) return 1; } q.pop_back(); return -1; } int main() { cin >> n >> m; for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { cin >> dp[i][j]; } } vector<vector<int>> q; // q.push_back({0, 0}); dfs(0, 0, q); q.push_back({n - 1, m - 1}); for(vector<int> t: q) { cout << "(" << t[0] << "," << t[1] << ")" << endl; } return 0; } // 64 位输出请用 printf("%lld")
深搜,最近练习C++刷题。