题解 | #按之字形顺序打印二叉树#
按之字形顺序打印二叉树
https://www.nowcoder.com/practice/91b69814117f4e8097390d107d2efbe0
层次遍历
思路
按照行层次遍历,这算是基本功了。
代码
/*
struct TreeNode {
int val;
struct TreeNode *left;
struct TreeNode *right;
TreeNode(int x) :
val(x), left(NULL), right(NULL) {
}
};
*/
class Solution {
public:
vector<vector<int> > Print(TreeNode* pRoot) {
vector<vector<int> > res;
if(!pRoot)
return res;
queue<TreeNode*> Q;
bool flag = false; //是否需要逆序
Q.push(pRoot);
while(!Q.empty())
{
vector<int> row;
queue<TreeNode*> QHelp;
while(!Q.empty())
{
TreeNode* node = Q.front();
Q.pop();
row.push_back(node->val);
if(node->left)
QHelp.push(node->left);
if(node->right)
QHelp.push(node->right);
}
Q = QHelp;
if(flag)
{
//逆序
reverse(row.begin(),row.end());
}
res.push_back(row);
flag = !flag; //这里容易toggle逻辑容易写错 是每次都需要取反的 而且取反符号是按照值取反!
}
return res;
}
};

