题解 | 查询连续入住多晚的客户信息？

 with t as (select ct.room_id,user_id,datediff(date(checkout_time),date(checkin_time)) as days,room_type
from checkin_tb ct
left join guestroom_tb gt
on gt.room_id = ct.room_id)
select user_id,room_id,room_type,days
from t 
where days >=2

order by days asc,room_id asc,user_id desc