题解 | 迷宫问题
迷宫问题
https://www.nowcoder.com/practice/cf24906056f4488c9ddb132f317e03bc
import java.util.*; // 注意类名必须为 Main, 不要有任何 package xxx 信息 public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); int m = in.nextInt(); int n = in.nextInt(); int[][] a = new int[m][n]; for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { a[i][j] = in.nextInt(); } } int[][] visited = new int[m][n]; dfs(a, 0, 0, m, n, visited); for (int[] ints : list) { System.out.println("(" + ints[0] + "," + ints[1] + ")"); } } static ArrayList<int[]> list = new ArrayList<>(); public static boolean dfs(int[][] a, int x, int y, int m, int n, int[][] visited) { if (x < 0 || x >= m || y < 0 || y >= n || a[x][y] == 1 || visited[x][y] == 1) { return false; } list.add(new int[] {x, y}); if (x == m - 1 && y == n - 1) { return true; } visited[x][y] = 1; if (dfs(a, x + 1, y, m, n, visited) || dfs(a, x, y + 1, m, n, visited) || dfs(a, x, y - 1, m, n, visited) || dfs(a , x - 1, y, m, n, visited)) { return true; } else { visited[x][y] = 0; list.remove(list.size() - 1); return false; } } }
这题使用dfs,题目只要求一条满足要求的路径就行了,并不需要求所有的路径,所有只要能够达到目的地就可以直接结束搜索过程,这点需要注意,这题有点疑问的是不知道如果转圈的话,会不会也算通过,没去尝试过