题解 | #字符串合并处理#
字符串合并处理
https://www.nowcoder.com/practice/d3d8e23870584782b3dd48f26cb39c8f
def change(x):
res="0123456789abcdefABCDEF"
if x in res:
temp=bin(int(x,16))[2:].rjust(4,'0')[::-1]
# 获得16进制数
return hex(int(temp,2))[2:].upper()
else: return x
strs=input().replace(' ','')
n=len(strs)
odd=""
even=""
for i in range(n):
if i%2==0:
even+=strs[i]
else: odd+=strs[i]
odd="".join(sorted(odd))
even="".join(sorted(even))
# print(odd,even,end=" ")
ans=""
for i in range(len(odd)):
ans+=even[i]+odd[i]
# print(ans)
if len(even)>len(odd):
ans+=even[-1]
ss=""
for i in range(len(ans)):
ss+=change(ans[i])
# print(change('y'))
print(ss)

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