题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.LinkedList;
/**
* 单链表删结点
* 法1:创建链表
* 法2:用linkedList
*
*/
public class Main {
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String[] s=br.readLine().split(" ");
int[] nums= new int[s.length-3];
int N=Integer.parseInt(s[0]);
int delete=Integer.parseInt(s[s.length-1]);
int head=Integer.parseInt(s[1]);
LinkedList<Integer> list = new LinkedList<>();
list.add(head);
for (int i = 2; i < s.length-2; i+=2)
list.add(list.indexOf(Integer.parseInt(s[i+1]))+1,Integer.parseInt(s[i]));
list.remove(list.indexOf(delete));
list.forEach(l-> System.out.print(l+" "));
}
}

