题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
while True:
try:
n = int(input())
list = input().split()
k = int(input())
print(list[len(list)-k])
except:
break
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