题解 | #删除链表的节点#
删除链表的节点
https://www.nowcoder.com/practice/f9f78ca89ad643c99701a7142bd59f5d
struct ListNode* deleteNode(struct ListNode* head, int val ) { // write code here if(head->val==val) return head->next; else{ struct ListNode* s=head; while(head->next!=NULL){ if(head->next->val==val){ head->next=head->next->next; } else{ head=head->next; } } return s; } }