题解 | #完全数计算#526ms通过
完全数计算
http://www.nowcoder.com/practice/7299c12e6abb437c87ad3e712383ff84
while True: try: n = int(input()) num = 0 for i in range(1,n+1): x = [j for j in range(1,i//2+1) if i%j == 0 and j != i] if sum(x) == i: num += 1 x.clear() print(num) except: break
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