select gender ,university ,count(1) as user_num ,round(avg(active_days_within_30),1) as avg_active_day ,round(avg(question_cnt),1) as avg_question_cnt from user_profile group by university ,gender order by gender asc, university asc; GROUP BY university, gender正确地按照“学校”和“性别”进行了双重分组。这意味着你会得到类似“北京大学-...