快速排序: 找出pivot索引,如果k大于pivot索引,那么结果就在pivot的右边,反之在左边,或者pivot索引刚好是答案 import java.util.*; public class Solution { private int result = -1; int partition(int []a, int left, int right) { int pivot = left; int index = pivot + 1; for (int i = index; i <= right; i++) { if (a[i] < a[pivot]) { swap(a, i, ...