SELECT university, COUNT(question_id) / COUNT(DISTINCT q.device_id) FROM user_profile u right JOIN question_practice_detail q ON u.device_id = q.device_id GROUP BY university ORDER BY university 这道题关键在于你要弄清楚两张表连接之后映射出来的表结构是怎样的。这里称user_profile为u表,question_practice_detail为q表。q表的device_id肯定是能在u表中映射得到的,...