题解 | 字符串加密

import re

# for line in sys.stdin:
#     a = line.strip().split()
#     print(list(a))
    # s = a[0]
    # t = a[1]
    # print(s,t)
s = input()
t = input()
zim = 'abcdefghijklmnopqrstuvwxyz'
# 直接把24个字母表加在字符串的最后，题目中说了以第一次出现的为准
s = s+zim
dic_a = {}
s_re = ""
end_s = ""
n = 97
for i in s:
    if i not in s_re:
        s_re += i
# print(s_re)
for i in s_re:
    # print(i)
    dic_a[chr(n)] = i
    n = n+1
# print(dic_a)
for i in t:
    end_s += dic_a[i]
print(end_s)