题解 | 牛牛学数列
牛牛学数列
https://www.nowcoder.com/practice/0b97367cd2184c12a0e02f7c223aee11
#include <stdio.h>
int main() {
int n;
scanf("%d",&n);
if(n==1)
{
printf("1");
}
else if(n%2==0)
{
int s=(n/2)*(-1);
printf("%d",s);
}
else if(n%2==1)
{
int c=(n/2)*(-1)+n;
printf("%d",c);
}
return 0;
}
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