题解 | 字符串构造判定python

#没有用到哈希表
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param ransomNote string字符串 
# @param magazine string字符串 
# @return bool布尔型
#
class Solution:
    def canConstruct(self , ransomNote: str, magazine: str) -> bool:
        # write code here
        if len(ransomNote)>len(magazine):
            return False
        for i in ransomNote:
            if ransomNote.count(i) > magazine.count(i):
                return False
        return True