题解 | #数位差与数值和的构造#

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>

using namespace std;

void solve() {
    string n_str;
    cin >> n_str;

    string a_str = "", b_str = "";
    bool turn_A = true;

    for (char c : n_str) {
        int digit = c - '0';
        int half = digit / 2;
        if (digit % 2 == 0) {
            a_str += to_string(half);
            b_str += to_string(half);
        } else {
            if (turn_A) {
                a_str += to_string(half + 1);
                b_str += to_string(half);
            } else {
                a_str += to_string(half);
                b_str += to_string(half + 1);
            }
            turn_A = !turn_A;
        }
    }

    // 使用stoll来处理可能的大数，并去除前导零
    cout << stoll(a_str) << " " << stoll(b_str) << endl;
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    int t;
    cin >> t;
    while (t--) {
        solve();
    }
    return 0;
}

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while (t-- > 0) {
            String nStr = sc.next();
            StringBuilder aStr = new StringBuilder();
            StringBuilder bStr = new StringBuilder();
            boolean turnA = true;

            for (char c : nStr.toCharArray()) {
                int digit = c - '0';
                int half = digit / 2;
                if (digit % 2 == 0) {
                    aStr.append(half);
                    bStr.append(half);
                } else {
                    if (turnA) {
                        aStr.append(half + 1);
                        bStr.append(half);
                    } else {
                        aStr.append(half);
                        bStr.append(half + 1);
                    }
                    turnA = !turnA;
                }
            }
            // 使用 Long.parseLong 来处理大数并去除前导零
            System.out.println(Long.parseLong(aStr.toString()) + " " + Long.parseLong(bStr.toString()));
        }
    }
}

import sys

def solve():
    n_str = sys.stdin.readline().strip()
    a_str = []
    b_str = []
    turn_A = True

    for char_digit in n_str:
        digit = int(char_digit)
        half = digit // 2
        if digit % 2 == 0:
            a_str.append(str(half))
            b_str.append(str(half))
        else:
            if turn_A:
                a_str.append(str(half + 1))
                b_str.append(str(half))
            else:
                a_str.append(str(half))
                b_str.append(str(half + 1))
            turn_A = not turn_A
    
    # 使用 int() 来处理大数并去除前导零
    print(int("".join(a_str)), int("".join(b_str)))


def main():
    t_str = sys.stdin.readline()
    if not t_str: return
    t = int(t_str)
    for _ in range(t):
        solve()

main()