题解 | 牛牛的矩阵相加
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
l = [[1,2,3],[4,5,6],[7,8,9]]
n = int(input())
for i in range(3):
for j in range(3):
l[i][j] *= n
print(l)
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
l = [[1,2,3],[4,5,6],[7,8,9]]
n = int(input())
for i in range(3):
for j in range(3):
l[i][j] *= n
print(l)
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