题解 | 单组_spj判断数组之和
单组_spj判断数组之和
https://www.nowcoder.com/practice/da783089da3b4a3188d240e1b7ac4b23
#include <stdio.h>
int main() {
int base=1;
long long n,m;
scanf("%lld %lld",&n,&m);
long long remainder=m-n;
long long extra=remainder/n;
long long additional=remainder%n;
for(int i=0;i<n;i++){
if(i<additional) printf("%lld ",base+extra+1);
else printf("%lld ",base+extra);
}
return 0;
}
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