F题求助
求个hack数据(dist没加第三维方向只能过40%,加了就AC了),想不到
不加方向
#include<bits/stdc++.h>
#define lc p << 1
#define rc p << 1 | 1
#define lowbit(x) x & -x
#define inv(x) qmi(x, P - 2)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef __int128 lll;
typedef pair<int,int> pii;
typedef pair<double,double> pdd;
typedef pair<ll,ll> pll;
const int N = 2e5 + 10;
const int inf = 0x3f3f3f3f;
const ll INF = 0x3f3f3f3f3f3f;
const double PI = 3.141592653;
const ll P = 1e9 + 7;
int T = 1;
ll qmi(ll a, ll b){
ll res = 1;
while(b){
if(b & 1) res = res * a % P;
b >>= 1;
a = a * a % P;
}
return res;
}
ll gcd(ll a, ll b){
return b ? gcd(b, a % b) : a;
}
void print_lll(lll x){
if(!x) cout << 0 << '\n';
else{
vector<int> nums;
while(x) nums.push_back(x % 10), x /= 10;
for(int i = 0; i < nums.size(); i ++) cout << nums[i];
}
}
void print(vector<ll> a, int n){
for(int i = 0; i < n; i ++){
if(i < n - 1) cout << a[i] << ' ';
else cout << a[i];
}
}
void solve(){
int n, m, h;
cin >> n >> m >> h;
vector<vector<char>> g(n + 10, vector<char>(m + 10));
int stx, sty, edx, edy;
for(int i = 1; i <= n; i ++)
for(int j = 1; j <= m; j ++){
cin >> g[i][j];
if(g[i][j] == '*') stx = i, sty = j;
if(g[i][j] == '%') edx = i, edy = j;
}
struct node{
int x, y, op, d;
bool operator<(const node&b) const{
return d > b.d;
}
};
auto check = [&](int x, int y) -> int{
return (x >= 1 && y >= 1 && x <= n && y <= m);
};
//这里注意:3个方向,dist只开2维会把不同方向的dist覆盖掉
vector<vector<int>> dist(n + 10, vector<int>(m + 10, inf));
priority_queue<node> heap;
heap.push({stx, sty, 0, 0});
dist[stx][sty] = 0;
while(heap.size()){
node t = heap.top();
heap.pop();
int x = t.x, y = t.y, op = t.op, d = t.d;
int ly = y - 1, ry = y + 1;
int nex = x + 1, ney = y;
if(!check(nex, ney)) continue;
if(!op){
if(g[nex][ney] == '#'){
if(check(x, ly) && g[x][ly] != '#' && dist[x][ly] > d + 1){
dist[x][ly] = d + 1;
heap.push({x, ly, 1, dist[x][ly]});
}
if(check(x, ry) && g[x][ry] != '#' && dist[x][ry] > d + 1){
dist[x][ry] = d + 1;
heap.push({x, ry, 2, dist[x][ry]});
}
if(dist[nex][ney] > d + h + 1){
dist[nex][ney] = d + h + 1;
heap.push({nex, ney, 0, dist[nex][ney]});
}
}
else{
if(dist[x + 1][y] > d + 1){
dist[x + 1][y] = d + 1;
heap.push({x + 1, y, 0, dist[x + 1][y]});
}
}
}
else if(op == 1){
if(g[x + 1][y] == '#'){
if(check(x, ly) && g[x][ly] != '#' && dist[x][ly] > d + 1){
dist[x][ly] = dist[x][y] + 1;
heap.push({x, ly, 1, dist[x][ly]});
}
}
else{
if(dist[x + 1][y] > d + 1){
dist[x + 1][y] = d + 1;
heap.push({x + 1, y, 0, dist[x + 1][y]});
}
}
}
else{
if(check(x + 1, y)){
if(g[x + 1][y] == '#'){
if(check(x, ry) && g[x][ry] != '#' && dist[x][ry] > d + 1){
dist[x][ry] = d + 1;
heap.push({x, ry, 2, dist[x][ry]});
}
}
else{
if(dist[x + 1][y] > d + 1){
dist[x + 1][y] = d + 1;
heap.push({x + 1, y, 0, dist[x + 1][y]});
}
}
}
}
}
// for(int i = 1; i <= n; i ++){
// for(int j = 1; j <= m; j ++){
// if(dist[i][j][1] == inf) cout << "- ";
// else cout << dist[i][j][0] << " ";
// }
// cout << '\n';
// }
int ans = dist[edx][edy];
cout << (ans == inf ? -1 : ans) << '\n';
}
int main(){
ios::sync_with_stdio(false);
cin.tie(0), cout.tie(0);
//cin >> T;
while(T --){
solve();
}
return 0;
}
加方向
#include<bits/stdc++.h>
#define lc p << 1
#define rc p << 1 | 1
#define lowbit(x) x & -x
#define inv(x) qmi(x, P - 2)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef __int128 lll;
typedef pair<int,int> pii;
typedef pair<double,double> pdd;
typedef pair<ll,ll> pll;
const int N = 2e5 + 10;
const int inf = 0x3f3f3f3f;
const ll INF = 0x3f3f3f3f3f3f;
const double PI = 3.141592653;
const ll P = 1e9 + 7;
int T = 1;
ll qmi(ll a, ll b){
ll res = 1;
while(b){
if(b & 1) res = res * a % P;
b >>= 1;
a = a * a % P;
}
return res;
}
ll gcd(ll a, ll b){
return b ? gcd(b, a % b) : a;
}
void print_lll(lll x){
if(!x) cout << 0 << '\n';
else{
vector<int> nums;
while(x) nums.push_back(x % 10), x /= 10;
for(int i = 0; i < nums.size(); i ++) cout << nums[i];
}
}
void print(vector<ll> a, int n){
for(int i = 0; i < n; i ++){
if(i < n - 1) cout << a[i] << ' ';
else cout << a[i];
}
}
void solve(){
int n, m, h;
cin >> n >> m >> h;
vector<vector<char>> g(n + 10, vector<char>(m + 10));
int stx, sty, edx, edy;
for(int i = 1; i <= n; i ++)
for(int j = 1; j <= m; j ++){
cin >> g[i][j];
if(g[i][j] == '*') stx = i, sty = j;
if(g[i][j] == '%') edx = i, edy = j;
}
struct node{
int x, y, op, d;
bool operator<(const node&b) const{
return d > b.d;
}
};
auto check = [&](int x, int y) -> int{
return (x >= 1 && y >= 1 && x <= n && y <= m);
};
//这里注意:3个方向,dist只开2维会把不同方向的dist覆盖掉
vector<vector<vector<int>>> dist(n + 10, vector<vector<int>>(m + 10, vector<int>(5, inf)));
priority_queue<node> heap;
heap.push({stx, sty, 0, 0});
dist[stx][sty][0] = 0;
while(heap.size()){
node t = heap.top();
heap.pop();
int x = t.x, y = t.y, op = t.op, d = t.d;
int ly = y - 1, ry = y + 1;
int nex = x + 1, ney = y;
if(!check(nex, ney)) continue;
if(!op){
if(g[nex][ney] == '#'){
if(check(x, ly) && g[x][ly] != '#' && dist[x][ly][1] > d + 1){
dist[x][ly][1] = d + 1;
heap.push({x, ly, 1, dist[x][ly][1]});
}
if(check(x, ry) && g[x][ry] != '#' && dist[x][ry][2] > d + 1){
dist[x][ry][2] = d + 1;
heap.push({x, ry, 2, dist[x][ry][2]});
}
if(dist[nex][ney][0] > d + h + 1){
dist[nex][ney][0] = d + h + 1;
heap.push({nex, ney, 0, dist[nex][ney][0]});
}
}
else{
if(dist[x + 1][y][0] > d + 1){
dist[x + 1][y][0] = d + 1;
heap.push({x + 1, y, 0, dist[x + 1][y][0]});
}
}
}
else if(op == 1){
if(g[x + 1][y] == '#'){
if(check(x, ly) && g[x][ly] != '#' && dist[x][ly][1] > d + 1){
dist[x][ly][1] = dist[x][y][1] + 1;
heap.push({x, ly, 1, dist[x][ly][1]});
}
}
else{
if(dist[x + 1][y][0] > d + 1){
dist[x + 1][y][0] = d + 1;
heap.push({x + 1, y, 0, dist[x + 1][y][0]});
}
}
}
else{
if(check(x + 1, y)){
if(g[x + 1][y] == '#'){
if(check(x, ry) && g[x][ry] != '#' && dist[x][ry][2] > d + 1){
dist[x][ry][2] = d + 1;
heap.push({x, ry, 2, dist[x][ry][2]});
}
}
else{
if(dist[x + 1][y][0] > d + 1){
dist[x + 1][y][0] = d + 1;
heap.push({x + 1, y, 0, dist[x + 1][y][0]});
}
}
}
}
}
// for(int i = 1; i <= n; i ++){
// for(int j = 1; j <= m; j ++){
// if(dist[i][j][1] == inf) cout << "- ";
// else cout << dist[i][j][0] << " ";
// }
// cout << '\n';
// }
int ans = inf;
for(int i = 0; i < 3; i ++) ans = min(ans, dist[edx][edy][i]);
cout << (ans == inf ? -1 : ans) << '\n';
}
int main(){
ios::sync_with_stdio(false);
cin.tie(0), cout.tie(0);
//cin >> T;
while(T --){
solve();
}
return 0;
}
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