题解 | 查询连续入住多晚的客户信息？

select user_id,room_id,room_type,datediff(checkout_time,checkin_time) as days
from checkin_tb a left join guestroom_tb b using(room_id)
where date(checkin_time)>='2022-06-12' and datediff(checkout_time,checkin_time)>1
order by days,room_id,user_id desc