题解 | #数字颠倒#
数字颠倒
https://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe
#include <iostream> #include <string> using namespace std; int main() { int num; cin>>num; string s1 = to_string(num); string s2; for(int i=s1.size()-1; i>=0; i--) { s2+=s1[i]; } cout<<s2<<endl; return 0; } // 64 位输出请用 printf("%lld")