题解 | #单组_spj判断数组之和#
单组_spj判断数组之和
https://www.nowcoder.com/practice/da783089da3b4a3188d240e1b7ac4b23
list_mn = input().split()
n = int(list_mn[0])
m = int(list_mn[1])
if (n-1)*n/2 < m :
for i in range(1,n+1):
if i < n:
print(i,end=' ')
else:
print(int(m - (n-1)*n/2))
else:
for i in range(n):
if i < n-1:
print(1,end=' ')
else:
print(m-n+1)
多投就行，同大二已经沟通2200➕了
