题解 | #计算日期到天数转换#

#include <stdio.h>

int main() {
    int year, month, day;
    while (scanf("%d %d %d", &year, &month, &day) != EOF) { 
        //存储每个月的天数
        int month_day[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
        //判断闰年
        if(year % 4 == 0 && year % 100 != 0 || year % 400 == 0) month_day[2] = 29;
        //加天数
        int days = 0;
        for(int i = 1; i < month; ++i) days += month_day[i];
        days += day;
        printf("%d",days);
    }
    return 0;
}