题解 | #字符串的反码#

#include <cctype>
#include <iostream>
using namespace std;
int main() {
   string s;cin>>s;
    for(int i =0;i<s.length();i++){
        if(islower(s[i])){
            int distance = s[i]-'a';
            s[i] = (char)('z'-distance);
        }else if(isupper(s[i])){
            int distance = s[i]-'A';
            s[i] = (char)('Z'-distance);
        }
    }
    cout<<s<<endl;
}
// 64 位输出请用 printf("%lld")

qd