题解 | #数值的整数次方#
数值的整数次方
https://www.nowcoder.com/practice/1a834e5e3e1a4b7ba251417554e07c00
class Solution { public: double Power(double base, int exponent) { if (exponent < 0){ // 碰到幂指数为负值,则更新一下基数与幂指数,方便统一计算 base = 1/base; exponent = -exponent; } double res = 1.0; for (int i = 0; i < exponent; ++i) { res*=base; } return res; } };
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