题解 | #井字棋#

#include <stdio.h>
int main() {
    char arr[3][3] = {0};
    int i = 0;
    int j = 0;
    char flag = 'c';
    for (i = 0; i < 3; i++) {
        for (j = 0; j < 3; j++) {
            scanf("%c", &arr[i][j]);
            getchar();
        }
    }
    for (i = 0; i < 3; i++) {
        if (arr[i][0] == arr[i][1] && arr[i][1] == arr[i][2]) {
            flag = arr[i][1];
            break;
        }
        if (arr[0][i] == arr[1][i] && arr[1][i] == arr[2][i]) {
            flag = arr[1][i];
            break;
        }
    }
    if (arr[0][0] == arr[1][1] && arr[1][1] == arr[2][2]) {
        flag = arr[1][1];
    }
    if (arr[0][2] == arr[1][1] && arr[1][1] == arr[2][0]) {
        flag = arr[1][1];
    }
    if (flag == 'K')
        printf("KiKi wins!");
    else if (flag == 'B')
        printf("BoBo wins!");
    else
        printf("No winner!");
    return 0;
}