题解 | #牛群的树形结构重建#
牛群的树形结构重建
https://www.nowcoder.com/practice/bcabc826e1664316b42797aff48e5153
import java.util.*;
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param inOrder int整型一维数组
* @param postOrder int整型一维数组
* @return TreeNode类
*/
public TreeNode buildTree (int[] inOrder, int[] postOrder) {
// write code here
if(inOrder.length ==0){
return null;
}
int rootVal = postOrder[postOrder.length -1];
TreeNode result = new TreeNode(rootVal);
int index = findRootIndex(inOrder,rootVal);
TreeNode left = buildTree(Arrays.copyOfRange(inOrder,0,index),Arrays.copyOfRange(postOrder,0,index));
TreeNode right = buildTree(Arrays.copyOfRange(inOrder, index + 1,inOrder.length),Arrays.copyOfRange(postOrder,index,postOrder.length-1));
result.left = left;
result.right = right;
return result;
}
public int findRootIndex(int[] arr,int rootVal){
for(int i = 0; i < arr.length;i++){
if(arr[i] == rootVal){
return i;
}
}
return -1;
}
}
