题解 | #试卷完成数同比2020年的增长率及排名变化#

试卷完成数同比2020年的增长率及排名变化

https://www.nowcoder.com/practice/13415dff75784a57bedb6d195262be7b

#  各类试卷的做完次数  上半年  同期的增长率
# rank

with table1 as(
    select tag, date_format(start_time,"%Y") as start_year,
    date_format(submit_time,"%Y%m") as submit_time
    from exam_record left join examination_info using(exam_id)
    where month(submit_time) <= 6 
),
table2 as (
    select tag,start_year,
    count(submit_time) as exam_cnt
    # rank()over(partition by start_year order by submit_month) as exam_cnt_rank 
    from table1 
    group by tag, start_year
),
table3 as(
    select * , rank()over(partition by start_year order by exam_cnt desc) as exam_cnt_rank
    from table2 
),
table4 as(
    select tag , 
    max(if(start_year = '2020',exam_cnt,0)) as exam_cnt_20,
    max(if(start_year = '2021',exam_cnt,0)) as exam_cnt_21,
    max(if(start_year = '2020',exam_cnt_rank,0)) as exam_cnt_rank_20,
    max(if(start_year = '2021',exam_cnt_rank,0)) as exam_cnt_rank_21
    from table3
    group by tag
)
select tag,exam_cnt_20,exam_cnt_21,
concat(round(((exam_cnt_21 - exam_cnt_20)/exam_cnt_20) * 100,1),'%') as growth_rate,
exam_cnt_rank_20,exam_cnt_rank_21,
(exam_cnt_rank_21 - exam_cnt_rank_20) as rank_delta
from table4
where exam_cnt_rank_21 != 0 and exam_cnt_rank_20 != 0
order by growth_rate desc,exam_cnt_rank_21 desc

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03-26 13:04
已编辑
电子科技大学 算法工程师
xiaowl:你这个简历“条目上”都比较有深度性,但是实际上面试官又没法很好的评估你是怎么达到很多看上去很厉害的结果的。要避免一些看上去很厉害的包装,比如高效的内存复用策略的表达,如果仅是简单的一些内存共享机制,而且面试上也没有深挖的空间,就不要这样表达。比如,工程化模式本质上可能就是定义了一些abstract class,那也就没特别多值得讲的内容。建议简历上应该侧重那些你花了大量时间和精力解决、研究的问题,不要过分追求“丰富”,而是关注在技术深入度、问题解决能力的表现上。
没有实习经历,还有机会进...
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