题解 | #删除链表的节点#

/**
 * struct ListNode {
 *	int val;
 *	struct ListNode *next;
 * };
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param head ListNode类 
 * @param val int整型 
 * @return ListNode类
 */
struct ListNode* deleteNode(struct ListNode* head, int val ) {
    // write code here
    struct ListNode *dummyHead = (struct ListNode*)malloc(sizeof(struct ListNode));//申请内存
    dummyHead->next = head;
    struct ListNode *cur = dummyHead;
    while(cur->next != NULL){
        if(cur->next->val == val){
            struct ListNode *tmp = (struct ListNode*)malloc(sizeof(struct ListNode));
            tmp = cur->next;
            cur->next = cur->next->next;            
            free(tmp);//释放内存
        }
        else cur = cur->next;
    }
    head = dummyHead->next;
    free(dummyHead);
    return head;
}