题解 | #根据状态转移图实现时序电路#
根据状态转移图实现时序电路
https://www.nowcoder.com/practice/e405fe8975e844c3ab843d72f168f9f4
`timescale 1ns/1ns
module seq_circuit(
input C ,
input clk ,
input rst_n,
output wire Y
);
reg [1:0] Cur_state ;
reg [1:0] Nxt_state ;
reg y;
always@(posedge clk or negedge rst_n) begin
if(!rst_n) begin
Cur_state <= 0;
end
else
Cur_state <= Nxt_state ;
end
always@(* ) begin
case(Cur_state)
2'b00:if(C==0) begin
Nxt_state = 2'b00 ;
y = 0;
end
else begin
Nxt_state = 2'b01 ;
y=0;
end
2'b01:if(C==0) begin
Nxt_state = 2'b11 ;
y = 0;
end
else begin
Nxt_state = 2'b01 ;
y=0;
end
2'b11:if(C==0) begin
Nxt_state = 2'b11 ;
y = 1;
end
else begin
Nxt_state = 2'b10 ;
y=1;
end
2'b10:if(C==0) begin
Nxt_state = 2'b00 ;
y = 0;
end
else begin
Nxt_state = 2'b10 ;
y=1;
end
endcase
end
assign Y = y ;
endmodule

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