题解 | #SQL100#

select c.cust_name, SUM(o2.item_price*o2.quantity) as total_price
from Orders o1 
inner join OrderItems o2 on o1.order_num = o2.order_num
inner join Customers c on o1.cust_id = c.cust_id
group by c.cust_name
having total_price >= 1000
order by total_price asc;

三表联合查询+group by(注意除了group by 的字段和聚合函数，其他的字段不能出现在select语句中)