题解 | #比较版本号#
比较版本号
https://www.nowcoder.com/practice/2b317e02f14247a49ffdbdba315459e7
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
# 比较版本号
# @param version1 string字符串
# @param version2 string字符串
# @return int整型
#
class Solution:
def compare(self , version1: str, version2: str) -> int:
# write code here
v1 = version1.split('.')
v2 = version2.split('.')
i=0
while i<len(v1) or i<len(v2):
if i>=len(v1):
t1 = 0
else:
t1 = int(v1[i])
if i>=len(v2):
t2 = 0
else:
t2 = int(v2[i])
if t1>t2:
return 1
elif t1<t2:
return -1
else:
i+=1
return 0
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