题解 | #获取每个部门中当前员工薪水最高的相关信息#

with t1 as(
    select de.emp_no, dept_no, salary
    from dept_emp de
    left join salaries sa
    on de.emp_no = sa.emp_no
),
t2 as (
    select *,
    row_number() over (partition by dept_no order by salary desc) as rk
    from t1
)
select dept_no, emp_no, salary
from t2
where rk = 1
order by dept_no

先进行关联，再用窗口函数