题解 | #蛇形矩阵#
蛇形矩阵
https://www.nowcoder.com/practice/649b210ef44446e3b1cd1be6fa4cab5e
思路:前n项和公式
N = int(input()) for i in range(N): l = [n*(n+1)//2-i for n in range(1,N+1)] # 每行根据公式更新列表l print(*l[i:])
以N=5为例:
蛇形矩阵
https://www.nowcoder.com/practice/649b210ef44446e3b1cd1be6fa4cab5e
N = int(input()) for i in range(N): l = [n*(n+1)//2-i for n in range(1,N+1)] # 每行根据公式更新列表l print(*l[i:])
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