题解 | #根据状态转移图实现时序电路#
根据状态转移图实现时序电路
https://www.nowcoder.com/practice/e405fe8975e844c3ab843d72f168f9f4
这一题很明显采用三段式状态机进行编写,需要注意的是第三段需要使用组合逻辑,而不能使用时序逻辑,采用时序逻辑会报错,错误显示,输出要和输入同时变化,所以需要组合逻辑 `timescale 1ns/1ns module seq_circuit( input C , input clk , input rst_n, output wire Y ); localparam Zero = 2'b00; localparam One = 2'b01; localparam Two = 2'b10; localparam Thre = 2'b11; reg [1:0] cur_state; reg [1:0] nex_state; reg Y_temp; assign Y = Y_temp; always@(posedge clk or negedge rst_n) begin if(!rst_n) cur_state <= Zero; else cur_state <= nex_state; end always@(*) begin nex_state = Zero; case(cur_state) Zero : begin if(C) nex_state = One; else nex_state = Zero; end One : begin if(C) nex_state = One; else nex_state = Thre; end Two : begin if(C) nex_state = Two; else nex_state = Zero; end Thre : begin if(C) nex_state = Two; else nex_state = Thre; end default : nex_state = Zero; endcase end always@(*) //这里需要注意的是,我们之前都是写的时序逻辑,而此题需要写组合逻辑,因为在报错中我们可以看到,其要求的是在C变化时,输出直接就变化,没有时序的采样过程 begin if(!rst_n) Y_temp <= 1'b0; else begin case(cur_state) Zero : begin Y_temp <= 1'b0; end One : begin Y_temp <= 1'b0; end Two : begin if(C) Y_temp <= 1'b1; else Y_temp <= 1'b0; end Thre : begin Y_temp <= 1'b1; end default : Y_temp <= 1'b0; endcase end end endmodule