题解 | #重复出现的字符串#
重复出现的字符串
https://www.nowcoder.com/practice/74a1dcc46607402780b6f6fc30241b2d
target = input()
patten = input()
index, count, i = -1, 0, 0
while i < len(target):
if target[i] == patten[0] and i + len(patten) <= len(target):
flag = True
for j in range(len(patten)):
if target[i+j] != patten[j]:
flag = False
break
if flag == True:
count += 1
if count == 1:
index = i
i = i + len(patten)-1
i += 1
print(count)
patten = input()
index, count, i = -1, 0, 0
while i < len(target):
if target[i] == patten[0] and i + len(patten) <= len(target):
flag = True
for j in range(len(patten)):
if target[i+j] != patten[j]:
flag = False
break
if flag == True:
count += 1
if count == 1:
index = i
i = i + len(patten)-1
i += 1
print(count)
print(index)
不知道有没有内置函数可以直接用，我这是一遍循环来查找的
#Python#
