题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
http://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
while True:
try:
node_count = int(input())
l = input()
k = int(input())
l = l.split(" ")
print(l[-k])
except:
break