题解 | #提取不重复的整数#
提取不重复的整数
http://www.nowcoder.com/practice/253986e66d114d378ae8de2e6c4577c1
#include #include using namespace std;
int main() { string s; cin >> s; string s1; int j = 0; for (int i = s.length() - 1; i >= 0; i--) { if (s1.find(s[i]) == -1) { cout << s[i]; s1 += s[i]; //cout << s1<< endl; j++; } }
return 0;
}
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