5.15微众银行前端实习笔试
笔试题型:55分选择题,45分问答题
问答题就是三道编程题,但是问答题自然是无法使用编译器的,真·手写代码
之所以特意写一篇帖子就是想问一下,一般这种编程题放到问答题是什么心态呀,他不方便改,我也不方便写,虽说可以考验我debug能力或者对API的熟练度,但是这么多卷子他们真的会去改吗,我有bug他们真的看得出来吗。。
然后帖一下三道问答题吧:
// 1.数组转树,笔试的时候少写了异步map.get()为空的判断
const nodes = [{id:1,parentId:null,name:'广东'},{id:2,parentId:1,name:'深圳'},{id:3,parentId:1,name:'杭州'}]
function transformTree(nodes){
let map = new Map()
let root = null
for(let i=0;i<nodes.length;i++){
// 记下parentId对应的结点数组
if(nodes[i].parentId == null){
root = nodes[i]
continue
}
let list = map.get(nodes[i].parentId)?map.get(nodes[i].parentId):new Array()
list.push(nodes[i])
map.set(nodes[i].parentId,list)
}
// 找到对应父亲id的结点们
const deepSearch = function(id){
let arr = []
if(!map.get(id)) return
for(let x of map.get(id)){
let obj = {}
obj.id = x.id
obj.name = x.name
// obj.children = deepSearch(x.id)
arr.push(obj)
}
return arr
}
let rootObj = {}
rootObj.id = root.id
rootObj.name = root.name
rootObj.children = deepSearch(root.id)
return rootObj
}
console.log(transformTree(nodes)) // 2.数组去重,笔试的时候有一个数组名arr没改回来,JSON.stringify写成了stringly哈哈,并且这里要用toString()才对的上样例,不过很扯,{a:1}==={a:2}?[1,2,3]==="1,2,3"?
// in :[123,"webank",[1,2,3],"123",{a:1},"tencent",123,[1,2,3],{a:2}]
// out:[123,"webank",[1,2,3],"123",{a:1},"tencent"]
// 关键点,数组与对象的去重,笔试的时候采取了Json.stringify()转换存储,好像应该用toString()方法
let initArr = [123,"webank",[1,2,3],"123",{a:1},"tencent",123,[1,2,3],{a:2}]
function deal(arr){
let map = new Map()
let newArr = []
for(let i=0;i<arr.length;i++){
let x = typeof arr[i] == 'object'?arr[i].toString():arr[i]
if(map.get(x)) continue //map里存在了,不操作
map.set(x,1)
newArr.push(arr[i])
}
return newArr
}
let newArr = deal(initArr)
console.log(newArr) // 3.求两个日期中间的有效日期,笔试的时候for的一个;手抖写成了:,monthArr的声明没写成let,习惯性写了const
// in:2020-9-29,2020-10-3
// out:['2020-9-29','2020-9-30','2020-10-1','2020-10-2','2020-10-3']
// 这里采用模拟的形式,Date()类的API有点忘了,不知道能不能直接通过API实现
function deal(dateA,dateB){
let ansArr = []
let [yearA,monthA,dayA] = dateA.split('-')
yearA=parseInt(yearA); monthA=parseInt(monthA);dayA=parseInt(dayA);
let [yearB,monthB,dayB] = dateB.split('-')
yearB=parseInt(yearB); monthB=parseInt(monthB);dayB=parseInt(dayB);
for(let year=yearA;year<=yearB;year++){
let monthArr = []
if((year%4==0 && year%100!=0) || (year%400==0)) monthArr=[31,29,31,30,31,30,31,31,30,31,30,31] //闰年
else monthArr=[31,28,31,30,31,30,31,31,30,31,30,31] //非闰年
let monthStart = year==yearA?monthA:1 //与起始年同一年就按给定的起始月走,否则从1月开始走
let monthEnd = year==yearB?monthB:12 //与结尾年同一年就按给定的最终月走,否则走到12月
for(let month=monthStart;month<=monthEnd;month++){
let dayStart = (year==yearA&&month==monthA)?dayA:1 //与起始年月都相同就按给定的天走,否则从1号开始走
let dayEnd = (year==yearB&&month==monthB)?dayB:monthArr[month-1] //与结尾年月都相同就按给定的天结束,否则走到月底
for(let day=dayStart;day<=dayEnd;day++){
let date = `${year}-${month}-${day}`
ansArr.push(date)
}
}
}
return ansArr
}
let dateArr = deal("2020-9-29","2020-10-3")
console.log(dateArr) 
