题解 | #统计字符#

正则表达式匹配

import re
while True:
    try:
        sentence = list(input().strip())
        a, b, c, d = 0, 0, 0, 0
        for item in sentence:
            if re.match('[a-zA-Z]', item):
                a += 1
            elif item == ' ':
                b += 1
            elif re.match('[0-9]', item):
                c += 1
            elif re.match('[^a-zA-Z0-9]', item):
                d += 1
        print(a)
        print(b)
        print(c)
        print(d)
    except:
        break