import java.util.*; public class Solution { public int InversePairs(int [] array) { return merge(array, 0, array.length - 1); } public int merge(int[] nums, int start, int end) { if (start >= end) { //分解到不能分解的时候的边界 return 0; } int mid = (start + end) / 2; // mid为中心左右各一半 int count = 0; count += me...