# 2个表都需要 # select * from user_profile u,question_practice_detail q where u.device_id=q.device_id; # select university,count(u.device_id) d from user_profile u,question_practice_detail q where u.device_id=q.device_id group by university select a.university,b.q1/a.d from (select university,count(disti...