题解 | 删除有序链表中重复的元素-I
删除有序链表中重复的元素-I
https://www.nowcoder.com/practice/c087914fae584da886a0091e877f2c79
#include<unordered_set>
using namespace std;
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* ListNode(int x) : val(x), next(nullptr) {}
* };
*/
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @return ListNode类
*/
ListNode* deleteDuplicates(ListNode* head) {
if(head==nullptr)
return nullptr;
ListNode* fast=head;
ListNode* curr=head;
unordered_set<int>hash;
hash.insert(head->val);
while(curr!=nullptr){
while(hash.find(fast->val)!=hash.end()){
fast=fast->next;
if(fast==nullptr){
curr->next=fast;
return head;}
}
hash.insert(fast->val);
curr->next=fast;
curr=fast;
}
return head;
}
};
