题解 | 反转链表
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
/**
* class ListNode(var `val`: Int) {
* var next: ListNode? = null
* }
*/
object Solution {
/**
* 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
*
*
* @param head ListNode类
* @return ListNode类
*/
fun ReverseList(head: ListNode?): ListNode? {
var cur = head
var pre:ListNode ?= null
var next :ListNode ?= null
while (cur!=null){
next = cur.next
cur.next = pre
pre = cur
cur = next
}
return pre
}
}
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