题解 | 简单计算器
简单计算器
https://www.nowcoder.com/practice/b8f770674ba7468bb0a0efcc2aa3a239
#include <stdio.h>
int main() {
double a,c,sum;
char b;
scanf("%lf%c%lf",&a,&b,&c);
if(b=='/')
{
if(c==0.0)
{
printf("Wrong!Division by zero!");
}
else{
sum=a/c;
printf("%.4lf/%.4lf=%.4lf",a,c,sum);
}
}
if(b=='*')
{
sum=a*c;
printf("%.4lf*%.4lf=%.4lf",a,c,sum);
}
if(b=='+')
{
sum=a+c;
printf("%.4lf+%.4lf=%.4lf",a,c,sum);
}
if(b=='-')
{
sum=a-c;
printf("%.4lf-%.4lf=%.4lf",a,c,sum);
}
if(b!='*'&&b!='-'&&b!='+'&&b!='/')
{
printf("Invalid operation!");
}
return 0;
}


