题解 | 牛牛的通勤
牛牛的通勤
https://www.nowcoder.com/practice/1fe33d534843473eb086c4b42655e13d
#include <stdio.h>
#include <math.h>
int main() {
int distance,time1,time2;
int v1 = 1;
int v2 = 10;
scanf("%d",&distance);
time1 = distance / v1;
time2 = ceil(distance / v2) + 10;
int time = (time1 < time2)?time1 :time2;
if( time1 == time){
printf("w");
}
if( time2 == time){
printf("v");
}
return 0;
}
