题解 | 字母异位词的长度python

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param s string字符串 
# @param c string字符串 
# @return int整型
#
class Solution:
    def isCongruent(self , s: str, c: str) -> int:
        # write code here
        if len(s)!=len(c):
            return -1
        dics = {}
        dicc = {}
        for i in range(97,123):
            if chr(i) in s:
                dics[chr(i)] = s.count(chr(i))
            if chr(i) in c:
                dicc[chr(i)] = c.count(chr(i))
        if dicc != dics:
            return -1
        return len(s)