题解 | 【模板】序列操作
【模板】序列操作
https://www.nowcoder.com/practice/12da4185c0bb45918cfdc3072e544069
import sys def solve(): input = sys.stdin.read data = input().split() # 数据读取 # print(data) ['5', '1', '8', '1', '9', '7', '1', '6', '8'] n = int(data[0]) seq = [] index = 1 output_lines = [] for _ in range(n): op = data[index]; index += 1 if op == '1': x = int(data[index]); index += 1 seq.append(x) elif op == '2': # if seq: seq.pop() elif op == '3': i = int(data[index]); index += 1 # print(seq[i]) output_lines.append(str(seq[i])) elif op == '4': i = int(data[index]); index += 1 x = int(data[index]); index += 1 seq.insert(i+1, x) # 在 下标 i和i+1间插入x elif op == '5': seq.sort() # 从小到大排序 elif op == '6': seq.sort(reverse=True) elif op == '7': # print(len(seq)) output_lines.append(str(len(seq))) elif op == '8': # print(' '.join(map(str,seq))) # ' '.join 拼接字符串 # map(函数, 可迭代对象) output_lines.append(' '.join(map(str, seq))) # 输出所有结果 print('\n'.join(output_lines)) solve()
结果收集后再输出 26ms
结果实时输出 88ms