题解 | 删除字符串中出现次数最少的字符

#include <climits>
#include <iostream>
#include<bits/stdc++.h>
using namespace std;

int main() {
    int a[26] = {0};
    char s;
    vector<char>vec;
    while (cin >> s) {
        a[s - 'a']++;
        vec.push_back(s);
    }

    int t1 = INT_MAX;
    vector<int>record;
    for (int i = 0; i < 26; i++) {
        if (a[i] > 0 && a[i] < t1) {
            t1 = a[i];
            record.clear();
            record.push_back(i);
        }
        if (a[i] == t1) {
            record.push_back(i);
        }
    }
    int k=record.size()-1;
    while(k>=0){
    for(int i=0;i<vec.size();i++){
    if (vec.size() == 1) {
        
        break;
    }
        if(k>-1&&vec[i]=='a'+record[k]){
            vec.erase(vec.begin()+i);
        }
    }
    k--;
    }
for(int i=0;i<vec.size();i++){
    cout<<vec[i];
}
cout<<endl;

}
// 64 位输出请用 printf("%lld")

虽史山代码但通过。