题解 | 判断各类型字符个数

str = input()
dict = dict()
n = 0
m = 0 
o = 0
p = 0
for i in str:
   dict[i] = str.count(i)
#print(dict)

for k,v in dict.items():
   if(k.isalpha()):
       m += v
   elif(k.isdigit()):
       n += v
   elif(k.isspace()):
       o += v
   else:
       p += v

print(f"英文字母{m}数字{n}空格{o}其他{p}")